operator overloading and type conversion - PrivacyWall

https://stackoverflow.com/questions/10281334/c-overloading-conver...

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C++ Overloading Conversion Operators - Stack Overflow

In this case you should mark the conversion operator as const since it doesn't affect the internal state of the object. ... @MihaiTodor If data has a complex type I'd say that's all the more reason to use an initialization list instead of assignment. ... Using operator overloading inside a function with const type input parameters in ...

https://www.geeksforgeeks.org/operator-overloading-cpp/

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Operator Overloading in C++ - GeeksforGeeks

in C++, Operator overloading is a compile-time polymorphism. It is an idea of giving special meaning to an existing operator in C++ without changing its original meaning. ... Type conversion means converting one type of data to another compatible type such that it doesn't lose its meaning. It is essential for managing different data ...

https://en.cppreference.com/w/cpp/language/cast_operator

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User-defined conversion function - cppreference.com

conversion-type-id is a type-id except that function and array operators [] or are not allowed in its declarator (thus conversion to types such as pointer to array requires a type alias/typedef or an identity template: see below). Regardless of typedef, conversion-type-id cannot represent an array or a function type. Although the return type is not allowed in the declaration of a user-defined ...

https://www.learncpp.com/cpp-tutorial/overloading-typecasts/

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21.11 — Overloading typecasts – Learn C++ - LearnCpp.com

Typecasts should be generally be marked as explicit. Exceptions can be made in cases where the conversion inexpensively converts to a similar user-defined type. Our Dollars::operator Cents() typecast was left non-explicit because there is no reason not to let a Dollars object be used anywhere a Cents is expected.

https://gacbe.ac.in/pdf/ematerial/18MMA35E-U4.pdf

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Unit-IV Operator Overloading and Type Conversions

Operator overloading provides a flexible option for the creation of new definitions for most of the C++ operators. We can overload all the C++ operators except ... C applies automatic type conversion to the operands as per certain rules. Similarly, an assignment operation also causes the automatic type conversion. The type of data to the right ...

https://www.geeksforgeeks.org/typecast-overloading-in-cpp/

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Typecast Operator Overloading in C++ - GeeksforGeeks

class ClassName { private: // All private members public: //All public members, constructors, etc. // Typecast operator overloading operator TargetType() const { // Conversion logic } }; Examples of Typecast Operator Overloading in C++ Example 1: Conversion from Complex Number to Double using typecast operator overloading. C++

https://en.cppreference.com/w/cpp/language/operators

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operator overloading - cppreference.com

Canonical implementations. Besides the restrictions above, the language puts no other constraints on what the overloaded operators do, or on the return type (it does not participate in overload resolution), but in general, overloaded operators are expected to behave as similar as possible to the built-in operators: operator + is expected to add, rather than multiply its arguments, operator ...

https://en.wikibooks.org/wiki/C%2B%2B_Programming/Operators/Opera...

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C++ Programming/Operators/Operator Overloading - Wikibooks

Operator overloading (less commonly known as ad-hoc polymorphism) is a specific case of polymorphism ... (coercion) or explicitly (casting) converted to another type. Conversion operators must be member functions, and should not change the object which is being converted, so should be flagged as constant functions. The basic syntax ...

https://people.cs.vt.edu/~kafura/cs2704/op.overloading4.html

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7.4 Type Conversion and Operator Overloading - Virginia Tech

To remove this duplication a type conversion is defined that converts an "int" to an "X" and a single overloading for the case "X + X" is provided. Thus, both "int + X" and "X + int" are converted to the single case "X + X". An example of manipulating colors will be used to illustrate the use of type conversion and operator overloading.

https://arne-mertz.de/2015/01/operator-overloading-common-practic...

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Operator Overloading: Common Practice - Simplify C++!

To enable this, provide an explicit conversion operator to bool. Overloading operator! is not necessary in that case. Usual declaration and implementation: bool X::operator!() const { return !/*some evaluation of *this*/; } ... enabling an implicit conversion from a type X to bool means, any object of type X can also be implicitly ...

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